url各个部分获取方法

偶然看到了一个通过js获取URL协议hostname等方法的办法。
记录一下，免得忘记了
地址：http://james.padolsey.com/javascript/parsing-urls-with-the-dom/

把函数也记录一下吧！

`// This function creates a new anchor element and uses location
// properties (inherent) to get the desired URL data. Some String
// operations are used (to normalize results across browsers).

function parseURL(url) {
var a = document.createElement('a');
a.href = url;
return {
source: url,
protocol: a.protocol.replace(':',''),
host: a.hostname,
port: a.port,
query: a.search,
params: (function(){
var ret = {},
seg = a.search.replace(/^?/,'').split('&'),
len = seg.length, i = 0, s;
for (;i<len;i++) {
if (!seg[i]) { continue; }
s = seg[i].split('=');
ret[s[0]] = s[1];
}
return ret;
})(),
file: (a.pathname.match(//([^/?#]+)$/i) || [,''])[1],
hash: a.hash.replace('#',''),
path: a.pathname.replace(/^([/])/,'/$1'),
relative: (a.href.match(/tps?://[^/]+(.+)/) || [,''])[1],
segments: a.pathname.replace(/^//,'').split('/')
};
}`

使用方法：
`var myURL = parseURL('http://abc.com:8080/dir/index.html?id=255&m=hello#top');

myURL.file; // = 'index.html'
myURL.hash; // = 'top'
myURL.host; // = 'abc.com'
myURL.query; // = '?id=255&m=hello'
myURL.params; // = Object = { id: 255, m: hello }
myURL.path; // = '/dir/index.html'
myURL.segments; // = Array = ['dir', 'index.html']
myURL.port; // = '8080'
myURL.protocol; // = 'http'
myURL.source; // = 'http://abc.com:8080/dir/index.html?id=255&m=hello#top'`